Cleveland would host Tampa Bay in a tiebreaker game Monday if there were a three-way deadlock for the two A.L. wild-card berths, and the loser would play at Texas on Tuesday for the second spot.
Because each team split season series against the two others, winning percentage in games among all three was used to determine tiebreaker placement. Cleveland (7-5) had the highest at .583, followed by Tampa Bay (7-6) at .538 and Texas (5-8) at .385.
Given the choice, Cleveland opted to be “Team A” and host Monday, and Tampa Bay decided to be “Team B” and play on the road Monday. Texas became “Team C.”
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